 | | Re: My average set
|
| (...) Easy! Have an even number of sets, and not have a multiple that set spans the midpoint. (If there is no midpoint you take the average of the two around the midpoint). (...) If you had a collection which consisted of ten copies each of: (...) (20 years ago, 22-Dec-04, to lugnet.loc.au, FTX)
| |  | | Re: My average set
|
| (...) Bah! Anyone can do that!!! BTW after re-evaluating, I must amend my stats - my modal set is now [LEGOSet 9936] A significant portion of which are utilised (URL) here>. This may also mean my average & median are wrong, but I can't be bothered (...) (20 years ago, 22-Dec-04, to lugnet.loc.au, FTX)
| |  | | Re: My average set
|
| (...) I realised this about 30 seconds after posting... just had one of those moments I guess. (...) So it's true, you can make the data say whatever you want! Michael (20 years ago, 23-Dec-04, to lugnet.loc.au, FTX)
| |  | | Re: My average set
|
| (...) I think you emphasised the wrong word in that sentence. Try: "So it's true, you can make the data say whatever you want!" ;-) Cheers Richie Dulin Statistician of .loc.au (20 years ago, 23-Dec-04, to lugnet.loc.au, FTX)
| |