Subject:
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Re: BOW, A new brick wargame
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Newsgroups:
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lugnet.gaming
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Date:
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Wed, 22 Nov 2006 13:02:06 GMT
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Viewed:
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11467 times
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In lugnet.gaming, David Eaton wrote:
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In lugnet.gaming, Alban NANTY wrote:
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- You only need Bricks to play, even the dices are replaced with bricks.
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I think this is an absolutely fantastic idea! I love the concept, plus the
idea that it’s more statistically balanced. For instance, a normal 1d20 will
do something “somewhere” between 1 and 20, but the odds of a 1 are just as
likely as a 14 or a 20. In your version, you’re more likely to get a “middle
number”.
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Thanks! When I tried it I had some fun to throw the bricks and hope a good
result. And yes your are more confident in getting a good result when lauching a
lot of bricks than just launching a 1d20.
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I am curious if it might be more balanced to change the dice roll a bit,
though. As I’ve heard (someone else did a little research on this),
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Really? That interests me, could you please find the reference? Maybe I could
add a page on my website with some maths and probabilities explanations on how
the system is mathematically balanced?
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a studs-sideways roll will happen only about 27% of the time. What that means
is that (for example) a Brick Roll of 6, 7, 8, or 9 is virtually the same
thing. They’re all (on average) likely to result in a roll of 2 (actually
closer to 1.62, 1.89, 2.16, and 2.43 respectively).
In the experimentation, a studs-down roll happened about 48% of the time--
quite a bit more likely. It might help add a little more excitement to the
game if you counted these studs-down rolls instead of only the studs-sideways
rolls. For the above Brick Rolls of 6, 7, 8, 9, counting studs-down rolls
results in an average of 2.88, 3.36, 3.84, and 4.32 respectively, nearly
doubling the “normal” range of a result, but still keeping the “statistically
balanced” rolls.
Anyway, just a comment-- I haven’t play-tested it, so I’m not really sure
what the scope of most rolls are “supposed” to be. But something to think
about, anyway.
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Each Brick Roll is supposed to be done against another Brick Roll from your
opponent, so there’s no standard difficulty result. That means you only need one
brick more studs-sideways than your opponent to win. So a result of 1 can be
sufficient. Doing the same calculation, a Brick Roll with 3, 4 or 5 bricks will
give you a average result of 0.81, 1.08 and 1.35.
So if your brick roll use 3, 4 or 5 more bricks than the brick roll of your
opponent, on average you should win.
Thanks for giving me the chance to do this little maths. :-)
Yours.
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Message has 1 Reply:
 | | Re: BOW, A new brick wargame
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| (...) Finally I made this page. You can find it on my (URL), menu "Related Stuff" > "Game System". For those who want to analyse the balance of this game mechanism in detail! :-) (17 years ago, 9-Nov-07, to lugnet.gaming, FTX)
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Message is in Reply To:
| | Re: BOW, A new brick wargame
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| (...) I think this is an absolutely fantastic idea! I love the concept, plus the idea that it's more statistically balanced. For instance, a normal 1d20 will do something "somewhere" between 1 and 20, but the odds of a 1 are just as likely as a 14 (...) (18 years ago, 21-Nov-06, to lugnet.gaming, FTX)
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