 | | Re: Why Not...? —Kevin Loch
| | | | The easiest way to do it is to simply order an element, and receive some arbitrary quantity (i.e. a "box" or "bag" full). That quantity might vary from part to part but would be consistent on a per part basis. That would be by far the most efficient (...) (25 years ago, 2-Feb-00, to lugnet.dear-lego)
| | | | | | | | | | Re: Why Not...? —Tom Stangl
| | | | | (...) Crocodials, like in Peter Pan? ;-) (...) I would think that by the pound, with an understood margin of error, would be the most efficient, since they use scales to verify set contents right now. -- | Tom Stangl, Technical Support Netscape (...) (25 years ago, 2-Feb-00, to lugnet.dear-lego)
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