 | | Re: 3D matrix math question
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(...) OK... I think I understand what I was getting at here. When you introduce perspective then the distance of the conditional point from the line becomes important. Eg. if you have a point that is directly behind its line in a perspective free (...) (16 years ago, 14-Dec-08, to lugnet.cad.dev, FTX)
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| | Re: 3D matrix math question
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(...) Hmmm... Though I can't quite pin it down I have a suspicion that this has something to do with the spatial reduction cause by projection. What projection matrix are you using? Would a simple solution just be to move the conditional points (...) (16 years ago, 14-Dec-08, to lugnet.cad.dev, FTX)
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| | Re: 3D matrix math question
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(...) I am not the best in 3D, but if something outside the view frustum, you do not need to draw that. If you have the special case that only parts of what you should draw are outside the view frustum, I would go to calculate that values for a (...) (16 years ago, 14-Dec-08, to lugnet.cad.dev, FTX)
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| | Re: 3D matrix math question
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(...) Actually, the projected points are all that I am checking, and that's how it's supposed to work. (...) No. The way that conditional lines work is that if the two control points lie on the same side of the conditional line on the screen (in (...) (16 years ago, 14-Dec-08, to lugnet.cad.dev, FTX)
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| | Re: 3D matrix math question
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(...) If I understand correctly you shouldn't be checking on the projection, only on the full 3D transformed points. That means you should check after stage 2.5. You'll need the Z value to work out which side things lie on. Tim (16 years ago, 14-Dec-08, to lugnet.cad.dev, FTX)
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