![](/news/x.gif) | | Re: icosahedron in soccer-ball style John Gerlach
| | | (...) I changed it, because I was thinking you meant that each of the black triangles would have one side of length 4 (that connects to the white hexagon), and two sides of length 3 (that connect to the two ajoining black triangles within the (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
| | | | | | ![](/news/x.gif) | | Re: icosahedron in soccer-ball style Alan Findlay
| | | | | (...) Hoo, boy. How to explain without pictures? Hmmm... okay here goes... Suppose the following represented two black triangles set side by side, touching at one vertices... _ _ \/ \/ The sides represented by "_" are 1x4's connecting to white 1x4's (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture)
| | | | | | | | | | ![](/news/x.gif) | | Re: icosahedron in soccer-ball style John Gerlach
| | | | | Ok, now I understand what you're going for. Interesting idea! And I can imagine why you refered to it as a "pinwheel"... :-) I was stuck on using the equalateral triangles due to me having a large collection of (URL) Polydron> (gasp! A different (...) (21 years ago, 16-Sep-03, to lugnet.build.sculpture, FTX)
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