Subject:
|
Re: SSClagorpion - Compressor
|
Newsgroups:
|
lugnet.technic
|
Date:
|
Wed, 2 Jun 2004 18:38:03 GMT
|
Viewed:
|
19503 times
|
| |
|
|
In lugnet.technic, Steve Hassenplug wrote:
>
> So, my general assertion is that the "work" required to compress six small pumps
> is the same as the work required to compress one large pump. That should take
> into account the "pushback" pressure.
Ok, so my co-worker (with a degree in physics) said (after many calculations)
that the Work is directly related to the Volume.
Assuming 6 small pistons pump the same volume as 1 large piston, it will take
the same amount of work.
Keep in mind, with 1 piston, half the time you are doing no work, and half the
time you are doing a bunch of work. So, you should test 2 large vs 12 small.
|
|
Message has 1 Reply:
 | | Re: SSClagorpion - Compressor
|
| (...) One thing not represented in your calculations is time. Compressing one large pump takes more force than it takes to compress one small pump. With six small pumps seperated by 60 degress of phase. We can compress/expand six small pumps in the (...) (20 years ago, 2-Jun-04, to lugnet.technic)
|
Message is in Reply To:
| | Re: SSClagorpion - Compressor
|
| Often, at work on Friday afternoon, we have informal discussions about stuff completely unrelated to work. This morning, I stood up and looked over my cube walls (not hard, they're only 4 ft tall) and said I had a question. I didn't get much (...) (20 years ago, 2-Jun-04, to lugnet.technic)
|
300 Messages in This Thread:
(Inline display suppressed due to large size. Click Dots below to view.)
- Entire Thread on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
This Message and its Replies on One Page:
- Nested:
All | Brief | Compact | Dots
Linear:
All | Brief | Compact
|
|
|
|
