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In lugnet.people, Joakim Olsson writes:
> Hi there!
> Excuse me if i am totally lost here...
> Is it not so that a 6 letter password containing letters from A to Z and 0
> to 9, can have 36^6 different combinations and contains 48 bits in a unique
> order?
> A binary value containing 0 or 1 in 8 postitions is 2^8, equals 256
36^6 is about equal to 2^31. Maybe it was typical 5-character pw's that
resulted in 24-26 bits of true information...I don't remember for sure, it
was many months ago. OK, yes, <calculator poking> 36^5 is about equal to
2^26. Also, IIRC, I think many 5-character pw's were rejected during the
random statistical tests on grounds of being too short and simple. Most of
the random 6-character pw's went through OK. Anyway, 2^18 is open net hockey
and 2^24 is still not so great.
Thanks.
--Todd
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Message has 1 Reply:
 | | Re: LUGNET Memberships
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| I've been on a few BBSes, quite a while back now, and believe me, some of the passwords that I came up with were quite alphanumeric, and rather random. A hacker's chance of guessing a random, or even semi-random, password is therefore theoretically (...) (24 years ago, 25-Sep-00, to lugnet.people, lugnet.admin.general)
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Message is in Reply To:
| | Re: LUGNET Memberships
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| Hi there! Excuse me if i am totally lost here... Is it not so that a 6 letter password containing letters from A to Z and 0 to 9, can have 36^6 different combinations and contains 48 bits in a unique order? A binary value containing 0 or 1 in 8 (...) (24 years ago, 25-Sep-00, to lugnet.people, lugnet.admin.general)
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