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| (...) One of the things I did pickup from "my" answer is you need to have a sample frequency small enough that you are not going to get wind direction changes of 180 degrees or more. And I say or more, because it's important to the average which (...) (21 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) And if you stop and think about it for a second or two, you'll realize your special case really does deserve special consideration. The average is no wind at all, so the direction would be undefined. (21 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) Don't you get the same problem at 180, now? 170 + 190 = 170 +(-170) = 0 I think there are several readings that can give you more than one result. For example, if you take two readings of 90 and 270, what should the answer be? 0? 180? never (...) (21 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) Here a detailed explanation I found puttering with google. I can't remember how to solve these equations anymore. So have fun. :-) (URL) (21 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) If I remember right, the way we resolved this for real-world surveying problems and the like was to convert the degrees 180 < x < 360 into negative values relative to 0/north. 350 is -10, 270 is -90, etc. If x1 > 180 then x2 = 360 - x1 This (...) (21 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
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