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 | | Re: OT: Math Help
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| (...) Don't you get the same problem at 180, now? 170 + 190 = 170 +(-170) = 0 I think there are several readings that can give you more than one result. For example, if you take two readings of 90 and 270, what should the answer be? 0? 180? never (...) (19 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) Here a detailed explanation I found puttering with google. I can't remember how to solve these equations anymore. So have fun. :-) (URL) (19 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) If I remember right, the way we resolved this for real-world surveying problems and the like was to convert the degrees 180 < x < 360 into negative values relative to 0/north. 350 is -10, 270 is -90, etc. If x1 > 180 then x2 = 360 - x1 This (...) (19 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | Re: OT: Math Help
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| (...) I think using vector math (as you do above) is the right way to go. As for the special cases, meh, deal with it :) (19 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
| | | | | OT: Math Help
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| Figured I'd bounce this problem off the smart people in RTLTotonto...This was posted on an automation mailing list, with little resolution: I have a weather station which measures both the direction and speed of the wind and is connected to a PC to (...) (19 years ago, 5-Aug-05, to lugnet.org.ca.rtltoronto)
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