|
| | Re: Couldn't resist
|
| (...) Actually, when calculating the acceleration and taking the distance into account, it's not so bad. For my first attempt at solving this, I tried converting gravitational potential energy into kinetic energy. The resulting integral was (...) (23 years ago, 3-Jul-01, to lugnet.space, lugnet.off-topic.geek)
| | | | Re: Couldn't resist
|
| (...) Umm... It's not a poke. honest. Your value for the Earth-moon distance is off by a factor of ten. which means your answer should be 2.25ish days. And... The force of the moon's gravity doesn't really enter into this. We know Force = (...) (23 years ago, 3-Jul-01, to lugnet.space, lugnet.off-topic.geek)
| | | | Re: Couldn't resist
|
| (...) Calculus, yet another form of mathematics that I am unable to do in my life. Jesse Long (23 years ago, 3-Jul-01, to lugnet.space, lugnet.off-topic.geek)
| | | | Re: Couldn't resist
|
| (...) Then it should be 2:26. Assuming that the relative acceleration between the Earth and the Moon is the sum of their local accelerations due to gravity. And assuming that acceleration is directly proportional to the force of gravity. Ie, when (...) (23 years ago, 3-Jul-01, to lugnet.space, lugnet.off-topic.geek)
| | | | Re: Couldn't resist
|
| (...) That'd be dy/dx = 2x. (I knew that calculus'd come in handy one day!) ROSCO (23 years ago, 3-Jul-01, to lugnet.space, lugnet.off-topic.geek)
| |