Subject:
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Re: Off on a tangent (or a sine, anyway)
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Newsgroups:
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lugnet.off-topic.geek
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Date:
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Tue, 16 Jan 2001 23:32:33 GMT
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Viewed:
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136 times
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> and the low points occur along y=60. I don't mean to be difficult, but I'm
> trying to get it going from (0,180) to (162,60) in a single high:low cycle
> (whatever the term).
Well, that changes everything, yes.
> I've messed around a little further, and the equation:
>
> y=60cos(x/51.5)+120
>
> gets visually pretty close to what I'm looking for. Is there a more logical
> method than the try-and-try-again way I've used so far?
If cos(x/51.5) is close, then you are in radians (Shiri already correctly
explained where the 1.11 came from, and she's correct if your wavelength of
324 is in degrees. If it's in radians then you have to scale it:
cos freq (degrees) = 360 degrees / wavelength
cos freq (radians) = 2*pi / wavelength
which is 6.2831853... / 324 which is 1/51.5662, which is where your 51.5
came from (324 / 2 pi)
and if yMax is 180 and yMin is 60 then your amplitude is 60 and your
baseline is 60,
y = Amplitude * cos(freq * x) + Baseline
y = 60 cos (x/51.56620) + 60
(sin is the same as cos but offset by pi / 2)
so y = 60 sin ((x/51.5662) + pi /2) + 60 would also work
Mark W.
Note that it sounds like you want your x axis to be in degrees (where 1.11 x
instead of x/51.5662 would work) yet you're working in radians (pi radians =
180 degrees) the point being that if you want to scale your x axis you
should be certain whether you're talking about 324 degrees or 324 radians.
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Message is in Reply To:
| | Re: Off on a tangent (or a sine, anyway)
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| (...) Doh! I was trying to be so careful! I thought amplitude was the "height" from high to low--is it actually half that? At any rate, I meant to write the min occurs at y=60, so that the high points occur along the line y=180 and the low points (...) (24 years ago, 16-Jan-01, to lugnet.off-topic.geek)
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