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In lugnet.space, Steve Bliss writes:
> In lugnet.space, Kyle D. Jackson writes:
>
> > Sweet! That would be *so cool*! Imagine sitting out on the deck
> > looking up at the full moon, and all of a sudden it starts falling
> > towards you. If we ignore the gravitational damage to the earth
> > (tides, crust stresses, etc) and the fact that the earth is still
> > rotating, how long would you get to watch the moon before it landed
> > on you? The first person to answer will get a cookie(*)!
>
> I get 1 hour, 13 minutes. Or 2 hours, 26 minutes. If I could remember the
> derivitive of y = x^2, I'd be more precise.
That'd be dy/dx = 2x. (I knew that calculus'd come in handy one day!)
ROSCO
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Message has 2 Replies:
 | | Re: Couldn't resist
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| (...) Then it should be 2:26. Assuming that the relative acceleration between the Earth and the Moon is the sum of their local accelerations due to gravity. And assuming that acceleration is directly proportional to the force of gravity. Ie, when (...) (23 years ago, 3-Jul-01, to lugnet.space, lugnet.off-topic.geek)
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