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| In lugnet.build.mosaic, Bob Kojima wrote:
> Is it efficient to replace plates w/bricks in a plates studs up mosaic?
>
> I always thought it was ....
> bob kojima
Yes it is !
If you build larger mosaics, you'll see that it gets much heavier if you only
use plates. The more bricks you use, the lighter your finished mosaic will be.
The best method??
In my mosaic I searched for large areas to use bricks instead of plates (mainly
manual), but in the mean time I tried to preserve a "brickwall"-structure to
make it as sturdy as possible (because I don't like to glue my precious lego
elements).
If weight is a crucial factor then I suggest you do the following:
Calculate the total amount of studs in all the used bricks (A), and calculate
the total amount of bricks (B). The method where A divided by B gives the
biggest number is the method in which you replaced as many plates as possible
with bricks (and thus resulting in the lightest mosaic) by using as few bricks
as possible (don't forget to check "A" because 23/5 < 8/1 but 23 >> 8).
This method is not perfect: 2 1x1 bricks weigh more than 1 1x2 brick, but 2 1x8
bricks weigh less than 1 1x16 brick....
Alternative: implement the weight of every element (found on BrickLink) when
doing a piece-count.
Conclusion: the method using the fewest elements is not necessarily the best
method...
:-)
Maarten
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| In lugnet.build.mosaic, Maarten Steurbaut wrote:
> In lugnet.build.mosaic, Bob Kojima wrote:
> > Is it efficient to replace plates w/bricks in a plates studs up mosaic?
> >
> > I always thought it was ....
> > bob kojima
>
> Yes it is !
> If you build larger mosaics, you'll see that it gets much heavier if you only
> use plates. The more bricks you use, the lighter your finished mosaic will be.
>
> The best method??
> In my mosaic I searched for large areas to use bricks instead of plates (mainly
> manual), but in the mean time I tried to preserve a "brickwall"-structure to
> make it as sturdy as possible (because I don't like to glue my precious lego
> elements).
> If weight is a crucial factor then I suggest you do the following:
> Calculate the total amount of studs in all the used bricks (A), and calculate
> the total amount of bricks (B). The method where A divided by B gives the
> biggest number is the method in which you replaced as many plates as possible
> with bricks (and thus resulting in the lightest mosaic) by using as few bricks
> as possible (don't forget to check "A" because 23/5 < 8/1 but 23 >> 8).
> This method is not perfect: 2 1x1 bricks weigh more than 1 1x2 brick, but 2 1x8
> bricks weigh less than 1 1x16 brick....
> Alternative: implement the weight of every element (found on BrickLink) when
> doing a piece-count.
>
> Conclusion: the method using the fewest elements is not necessarily the best
> method...
>
> :-)
>
> Maarten
hi Maarten,
you bring up a good point. it never occurred to me that weight would also be an
issue. this now becomes a weight vs. part count efficiency problem.
i'm going to have to go find the weight of the parts i'm using and do some
calculating. i could probably spit out a total mosaic weight after the LDraw
file is made. humm...that would be interesting.
thanks,
bob
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